Physic Labs
In a frame moving at velocity v:ΔEbody kinetic=L(11−v2/c2−1)\text{In a frame moving at velocity } v: \quad \Delta E_{\text{body kinetic}} = L\left(\frac{1}{\sqrt{1-v^2/c^2}} - 1\right)
problems.proof.analysis

Observe the same process from a frame moving at velocity vv relative to the body. Due to relativistic Doppler shift, the total light energy measured in this frame is L/1−v2/c2L/\sqrt{1-v^2/c^2} instead of LL. This energy difference must come from somewhere — Einstein argued it equals the change in the body's kinetic energy (since the body still moves at velocity vv before and after emission, but has become 'lighter').