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Newton's law of universal gravitation

Statement

F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2} — the attractive force between two point masses m1,m2m_1, m_2 separated by rr, with gravitational constant G≈6.674×10−11 N⋅m2/kg2G \approx 6.674 \times 10^{-11}\ \text{N·m}^2/\text{kg}^2.

Why is it true?

Every massive object attracts every other; the force falls off with the square of distance, mathematically the same form as the Coulomb force between two charges.

Two orbiting bodies around their barycenter: change masses and separation to see the 1/r² gravitational force shape elliptical orbits.
Proof sketch

Newton derived this from Kepler's three empirical laws of planetary motion plus his own second law: assuming a circular orbit of radius r and period T, the required centripetal force is F=mω2r=m(2π/T)2rF = m\omega^2 r = m(2\pi/T)^2 r. Combined with Kepler's third law (T2∝r3T^2 \propto r^3), this gives F∝1/r2F \propto 1/r^2.

Stated by

Topics that use this theorem

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Step-by-step proofs

No step-by-step proof yet for this theorem.

References

  1. Isaac Newton (1687). Principia Mathematica