Physic Labs
kL=nπ ⇒ 2πλnL=nπ ⇒ λn=2Ln,n=1,2,3,…kL = n\pi \ \Rightarrow\ \frac{2\pi}{\lambda_n}L = n\pi \ \Rightarrow\ \lambda_n = \frac{2L}{n},\quad n=1,2,3,\ldots
problems.proof.analysis

The sine function is zero only at integer multiples of π\pi, so kLkL must equal nπn\pi for a positive integer nn (n=0 gives the trivial solution y≡0y\equiv 0, not a wave). Substituting k=2π/λk=2\pi/\lambda and solving for λn\lambda_n recovers exactly the stated standing-wave condition.