Physic Labs

Condensed matter physics

Bose–Einstein statistics

The Bose–Einstein distribution gives the mean occupation of bosonic states at thermal equilibrium. Bosons are not subject to Pauli exclusion and can share a state; under suitable density and temperature, macroscopic ground-state occupation can occur.

At equilibrium, state occupation depends on energy and chemical potential. For bosons, the number in a state is not limited by Pauli exclusion; the denominator approaches zero as energy approaches the chemical potential from above.

nˉi=1/(exp[(εi−μ)/(kBT)]−1)n̄ᵢ = 1 / (exp[(εᵢ − μ)/(kBT)] − 1)

Definition: Bose–Einstein distribution

n̄ᵢ is the mean occupation of a state of energy εᵢ; μ is the chemical potential, with μ ≤ ε₀, the lowest energy. The minus sign in the denominator distinguishes bosons from fermions.

Adjust temperature and density to explore quantum occupations and related quantities.

Temperature limits and condensation

At high temperature and low density, n̄ᵢ ≪ 1 and the distribution approaches Maxwell–Boltzmann. For a uniform three-dimensional ideal Bose gas below its critical temperature, particles exceeding the excited-state capacity can occupy the ground state: Bose–Einstein condensation.

λt=h/√(2πmkBT),nλt3≳2.612λₜ = h / √(2πmkBT), n λₜ³ ≳ 2.612

λₜ is the thermal de Broglie wavelength. nλₜ³ of order unity signals collective quantum behavior; the value 2.612 applies to a uniform ideal 3D Bose gas at the condensation threshold. Interactions and trap geometry modify details.

Example: Worked example

A bosonic mode has ε−μ = kBT ln 3. Find its mean occupation.

Solution

n̄ = 1/(e^(ln 3)−1)=1/2. This is an ensemble mean, not necessarily an integer in a single measurement.

A deeper view uses the fugacity z=eμ/(kBT)z=e^{\mu/(k_BT)} and the grand partition function. Each mode has Zi=(1−ze−βϵi)−1\mathcal Z_i=(1-ze^{-\beta\epsilon_i})^{-1}; differentiating with respect to chemical potential gives its mean occupation. As zz approaches its largest allowed value, excited modes cannot accommodate more particles at the same temperature and density. In a finite system the transition is rounded: condensation means macroscopic ground-state occupation, not an absolute singularity.

Quick check

Which sign appears in the Bose–Einstein denominator?

Which sign is in the denominator of the corresponding distribution?

References

  1. Landau, Lifshitz (1980). Statistical Physics
  2. Charles Kittel, Herbert Kroemer (1980). Thermal Physics