Physic Labs

Electricity and magnetism

The Lorentz force

The Lorentz force is the electromagnetic force on a moving charge, F⃗=q(E⃗+v⃗×B⃗)\vec F=q(\vec E+\vec v\times\vec B).

The Lorentz force is the electromagnetic force on a moving charge, F⃗=q(E⃗+v⃗×B⃗)\vec F=q(\vec E+\vec v\times\vec B).

F⃗=q(E⃗+v⃗×B⃗),r=mv⊥∣q∣B\vec F=q(\vec E+\vec v\times\vec B),\qquad r=\frac{mv_\perp}{|q|B}

Definition: Orbit in a uniform magnetic field

The electric part qE⃗q\vec E can change kinetic energy. The magnetic part qv⃗×B⃗q\vec v\times\vec B is perpendicular to velocity and does no work. For v⃗⊥B⃗\vec v\perp\vec B in a uniform magnetic field alone, the path is circular, with r=mv/(∣q∣B)r=mv/(|q|B) and T=2πm/(∣q∣B)T=2\pi m/(|q|B). The charge sign determines the rotation sense.

Adjust the controls and drag the view to explore the topic’s quantitative field, orbit, or waveform.

Reading the model

The electric part qE⃗q\vec E can change kinetic energy. The magnetic part qv⃗×B⃗q\vec v\times\vec B is perpendicular to velocity and does no work. For v⃗⊥B⃗\vec v\perp\vec B in a uniform magnetic field alone, the path is circular, with r=mv/(∣q∣B)r=mv/(|q|B) and T=2πm/(∣q∣B)T=2\pi m/(|q|B). The charge sign determines the rotation sense.

Example: Worked example

A proton (m=1.67×10−27m=1.67\times10^{-27} kg, q=1.60×10−19q=1.60\times10^{-19} C) moves at 2.0×1052.0\times10^5 m/s perpendicular to B=0.20B=0.20 T. Find its orbit radius.

Solution

r=mv/(qB)≈1.04×10−2r=mv/(qB)\approx1.04\times10^{-2} m.

The magnetic term qv⃗×B⃗q\vec v\times\vec B is always perpendicular to velocity, so magnetic force does no work even though it can bend a trajectory. For a particle entering a uniform field perpendicularly, the force supplies centripetal acceleration and the orbit radius is r=mv/(∣q∣B)r=mv/(|q|B). If velocity also has a component parallel to B⃗\vec B, that component remains unchanged and the particle follows a helix around the field line.

Changing the charge sign reverses Lorentz-force direction without changing its magnitude. Thus an electron moving through the same E⃗\vec E and B⃗\vec B feels force opposite to a proton with the same velocity.

Quick check

In a static magnetic field, the magnetic force on a point charge is always:

If a particle moves parallel to B⃗\vec B, the magnetic part of the force is:

References

  1. Young, Freedman (2019). University Physics