Physic Labs

Electricity and magnetism

Transformers and generators

A generator converts mechanical to electrical energy by induction; a transformer changes AC voltage according to its turns ratio.

A generator converts mechanical to electrical energy by induction; a transformer changes AC voltage according to its turns ratio.

UsUp=NsNp,UpIp≃UsIs\frac{U_s}{U_p}=\frac{N_s}{N_p},\qquad U_pI_p\simeq U_sI_s

Definition: Ideal transformer

Two coils on a common core are linked by changing magnetic flux. For an ideal transformer, RMS voltage ratio equals turns ratio, Us/Up=Ns/NpU_s/U_p=N_s/N_p, while power conservation gives UpIp=UsIsU_pI_p=U_sI_s. A transformer needs changing flux, usually supplied by AC. A generator induces emf as a rotating coil changes its flux; for NN turns of area AA rotating at angular speed ω\omega in BB, E0=NBAω\mathcal E_0=NBA\omega.

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Reading the model

Two coils on a common core are linked by changing magnetic flux. For an ideal transformer, RMS voltage ratio equals turns ratio, Us/Up=Ns/NpU_s/U_p=N_s/N_p, while power conservation gives UpIp=UsIsU_pI_p=U_sI_s. A transformer needs changing flux, usually supplied by AC. A generator induces emf as a rotating coil changes its flux; for NN turns of area AA rotating at angular speed ω\omega in BB, E0=NBAω\mathcal E_0=NBA\omega.

Example: Worked example

An ideal transformer has Np=500N_p=500, Ns=1000N_s=1000, Up=12U_p=12 V, and a load current Is=0.30I_s=0.30 A. Find UsU_s and IpI_p.

Solution

The turns ratio gives Us=12(1000/500)=24U_s=12(1000/500)=24 V. Output power is 24(0.30)=7.224(0.30)=7.2 W, so Ip=7.2/12=0.60I_p=7.2/12=0.60 A.

In a simple AC generator, flux through a rotating coil changes with time, so induced emf reverses periodically. Electrical energy does not appear spontaneously: an external drive supplies mechanical work, and the load receives energy through current. For an ideal transformer, power conservation gives UpIp=UsIsU_pI_p=U_sI_s; stepping voltage up by the turns ratio reduces secondary current correspondingly. Real devices are less than 100% efficient because of winding resistance, eddy currents, and flux leakage.

Quick check

An ideal transformer has Ns=2NpN_s=2N_p. Then:

An ideal transformer has Ns=3NpN_s=3N_p. The secondary voltage is:

References

  1. Young, Freedman (2019). University Physics