Physic Labs

Electricity and magnetism

Ohm's law for a circuit segment

Current is proportional to voltage and inversely proportional to resistance: I = U/R.

Ohm's law is the empirical rule describing the relationship between the voltage applied across a circuit segment and the current flowing through it, via resistance RR.

I=URI = \frac{U}{R}

UU is the voltage (volts, V) across the segment, II is the current (amperes, A), and RR is resistance (ohms, Ω) — a quantity that characterizes how much a material and wire shape resist current flow.

Definition: Resistance

The resistance of a uniform cylindrical wire depends on the material's resistivity ρ\rho, its length ll, and cross-section SS: R=ρl/SR = \rho l/S. A longer, thinner wire has more resistance — much like a long, narrow pipe resists flow more.

Watch electrons (blue dots) drift through the wire at a speed proportional to I. Drag the U, R sliders to see I = U/R change live on the graph.

Series and parallel circuits

When two resistors R1,R2R_1, R_2 are connected in series, the same current II flows through both, while the voltage splits in proportion to resistance:

Rtd=R1+R2,U1=IR1, U2=IR2R_{\text{td}} = R_1 + R_2, \qquad U_1 = IR_1,\ U_2 = IR_2

When connected in parallel, both branches share the same voltage UU, while the current splits inversely with resistance:

1Rtd=1R1+1R2,I1=UR1, I2=UR2\frac{1}{R_{\text{td}}} = \frac{1}{R_1} + \frac{1}{R_2}, \qquad I_1 = \frac{U}{R_1},\ I_2 = \frac{U}{R_2}

Example: Parallel circuit

Two resistors R1=6 ΩR_1 = 6\ \Omega and R2=12 ΩR_2 = 12\ \Omega are connected in parallel across a U=12U = 12 V source. Find the current in each branch and the total.

Solution

I1=U/R1=12/6=2I_1 = U/R_1 = 12/6 = 2 A, I2=U/R2=12/12=1I_2 = U/R_2 = 12/12 = 1 A. Total current I=I1+I2=3I = I_1 + I_2 = 3 A, consistent with Req=4 ΩR_{\text{eq}} = 4\ \Omega and I=U/Req=12/4=3I = U/R_{\text{eq}} = 12/4 = 3 A.

Ohm’s law is an empirical relation in the ohmic operating regime: at stable temperature and material conditions, doubling voltage doubles current. A graph of II against UU is a straight line through the origin with slope 1/R1/R. A lamp filament is not always linear because it heats as current flows; distinguish resistance at a particular state from an ohmic component whose RR is nearly constant.

Resistance can be determined by measuring the voltage across a resistor and the current through it. If U=9.0U=9.0 V and I=0.30I=0.30 A, then R=30 ΩR=30\,\Omega. When connecting a load, use consistent SI units and check its dissipated power, P=UI=2.7P=UI=2.7 W, as a reasonableness test for the measured current.

Quick check

Keeping voltage fixed, if the circuit's resistance triples, the current will:

Two equal resistors in parallel give an equivalent resistance equal to:

References

  1. Georg Simon Ohm (1827). Die galvanische Kette, mathematisch bearbeitet
  2. Young, Freedman (2019). University Physics