Physic Labs

Electrodynamics

Magnetostatics and the vector potential

Steady currents produce a divergence-free magnetic field; writing B = ∇×A automatically satisfies ∇·B = 0.

In magnetostatics, current density J is time independent. Ampère’s law fixes the curl of B, while the vector potential A is useful in boundary-value problems and quantum mechanics.

∇×B=μ0J,B=∇×A∇×B = μ₀J, B = ∇×A

Definition: Quantities and model

In Coulomb gauge ∇·A = 0 in vacuum, ∇²A = −μ₀J. For a thin wire, A(r) = μ₀I/(4π)∫dl′/|r−r′| and B = ∇×A.

Adjust parameters and rotate the view to inspect field structure; this is illustrative, not a general Maxwell solver.

Interpretation and consequences

A is not unique: the gauge change A′ = A + ∇χ leaves B unchanged. In electrodynamics, scalar potential φ and A give E = −∇φ − ∂A/∂t.

Example: Quantitative example

A long straight wire carrying I = 3 A gives B = μ₀I/(2πr). At r = 2 cm, B = 3.0×10⁻⁵ T.

Solution

Substitute into the stated relation, keep SI units consistent, and check the result dimensionally.

The vector potential depends on gauge, but its circulation around a closed loop is fixed: ∮A⋅dℓ=∫B⋅dS\oint A\cdot d\ell=\int B\cdot dS. This is Stokes's theorem applied to B=∇×AB=\nabla\times A. For a wire loop, changing magnetic flux gives the induced emf E=−dΦB/dt\mathcal E=-d\Phi_B/dt, so the potential links field geometry directly to electromagnetic induction.

In Coulomb gauge, each component of AA obeys a Poisson equation. Its integral solution depends on the whole current distribution, not just a point; taking the curl then yields BB. Another gauge may simplify a boundary condition or symmetry without changing observables. For time-dependent currents, this instantaneous integral must be replaced by a retarded potential to respect finite signal speed.

The integral vector-potential solution is nonlocal: currents at every source point contribute with weight 1/∣r−r′∣1/|r-r'|. In a simply connected region, Coulomb gauge selects a convenient representative, but boundaries and topology can leave residual freedom. For a thin wire, the circulation around a loop is tied to magnetic flux through any spanning surface; the chosen surface must be consistent with the source region and boundary conditions.

Quick check

Which relation is correct in the idealized situation described?

What should be checked first when applying a field formula?

References

  1. John David Jackson (1998). Classical Electrodynamics