Physic Labs

Thermal physics

Ideal gas equation of state

The ideal-gas state links pressure, volume, absolute temperature, and amount of substance through pV=nRT.

For a fixed amount of gas behaving ideally, pressure p, volume V, and absolute temperature T are not independent. The equation of state determines an unknown when the others are known.

pV=nRT=NkBTpV = nRT = Nk_B T

Definition: Variables and units

Use p in pascals (Pa), V in m³, T in kelvins (K), and n in moles. R=8.314R=8.314 J mol⁻¹ K⁻¹; for N molecules, kB=R/NAk_B=R/N_A. Temperature must be in kelvins.

Change volume and temperature; pressure responds according to the state equation for a fixed amount of gas.

One state, many paths

An equilibrium state is specified by p, V, T, and n. For fixed n, two states of the same gas satisfy p1V1/T1=p2V2/T2p_1V_1/T_1=p_2V_2/T_2. The path between them depends on how the gas is heated, compressed, or expanded.

Example: Find the pressure

One mole of ideal gas at 300 K occupies 0.024 m³. Find its pressure using R=8.314 J mol⁻¹ K⁻¹.

Solution

p=nRT/V=1×8.314×300/0.024≈1.04×105p=nRT/V=1\times8.314\times300/0.024\approx1.04\times10^5 Pa.

Quick check

For a fixed amount of gas, the equation of state lets you check a state when three variables are known. If temperature rises while volume is fixed, pressure rises in proportion to absolute temperature; at fixed pressure, warming the gas increases its volume. These variables are not independent: their values are constrained by the amount of gas and the gas constant. Use kelvins, cubic metres, and pascals with R=8.314R=8.314 J mol⁻¹ K⁻¹ for consistent units. The equation can be written pV=NkBTpV=Nk_BT when counting molecules NN, or pV=nRTpV=nRT when using amount nn in moles. The forms are connected by R=NAkBR=N_Ak_B. Real gases depart from this model when molecular volume or intermolecular forces become important, especially near condensation. Thus the ideal-gas law is a useful approximation with a physical range of validity, not a universal identity for every gas state.

For example, one mole of ideal gas at 300 K in a 0.024 m³ vessel has pressure p=nRT/Vapprox104p=nRT/Vapprox104 kPa. This is close to atmospheric pressure. If using RR in joules per mole-kelvin, convert litres to cubic metres before substituting.

Which unit must be used for T in pV=nRT?

At fixed n and V, what happens to p if T doubles?

References

  1. Halliday, Resnick, Walker (2014). Fundamentals of Physics