Physic Labs

Quantum mechanics

The hydrogen atom: energy levels and orbitals

The Coulomb potential gives hydrogen energy levels indexed by principal quantum number nn; orbitals ∣ψnlm∣2|\psi_{nlm}|^2 are probability densities, not planetary paths.

Hydrogen is the first exactly solvable Coulomb problem in quantum mechanics. Separating the Schrödinger equation in spherical coordinates yields states labeled by n,l,mln,l,m_l. Its simple spectrum explains spectral lines and underpins atomic structure.

En=−13.6 eVn2,n=1,2,...;l=0,...,n−1,ml=−l,...,lE_n=-\frac{13.6\,\mathrm{eV}}{n^2},\quad n=1,2,...;\qquad l=0,...,n-1,\quad m_l=-l,...,l

Definition: Quantum numbers

The principal number nn sets the energy and characteristic size. Orbital number ll sets angular momentum L2=l(l+1)ℏ2L^2=l(l+1)\hbar^2; magnetic number mlm_l gives its projection Lz=mlℏL_z=m_l\hbar. For each nn, there are n2n^2 states excluding spin in the nonrelativistic hydrogen model.

Select 1s, 2s, or 2p to inspect a spatial model of ∣ψnlm∣2|\psi_{nlm}|^2 and its nodes; the cloud represents probability, not a moving path.

Spectral lines and transitions

In the nonrelativistic Coulomb model, energy depends only on nn, so several states are degenerate. When the atom absorbs or emits a photon, its energy equals the level difference: hν=∣Ef−Ei∣h\nu=|E_f-E_i|. Fine structure and external effects partly lift the ideal degeneracy.

Example: Transition photon

An electron drops from n=3n=3 to n=2n=2. Find the emitted photon energy.

Solution

E2=−13.6/4=−3.40E_2=-13.6/4=-3.40 eV; E3=−13.6/9=−1.51E_3=-13.6/9=-1.51 eV. Emission gives Eγ=E3−E2=1.89E_\gamma=E_3-E_2=1.89 eV.

The Coulomb potential is spherically symmetric, so the problem separates into radial and angular parts. In the nonrelativistic model, energy depends on principal quantum number nn but is degenerate in l,ml,m; these label energy scale and orbital angular momentum. The Bohr radius a0=4πϵ0ℏ2/(mee2)a_0=4\pi\epsilon_0\hbar^2/(m_e e^2) sets the length scale, and bound levels are En=−13.6 eV/n2E_n=-13.6\,\text{eV}/n^2. Spectral lines occur when a photon satisfies hν=Ei−Efh\nu=E_i-E_f. Fine structure and QED corrections split levels that the basic Coulomb model treats as degenerate.

Quick check

In nonrelativistic hydrogen, which quantum number directly determines the energy?

What does an atomic orbital represent?

References

  1. David J. Griffiths, Darrell F. Schroeter (2018). Introduction to Quantum Mechanics