Physic Labs

Fluid mechanics

Archimedes’ principle

An object immersed in a fluid experiences an upward buoyant force equal to the weight of the displaced fluid.

An object feels lighter underwater because the surrounding fluid exerts a net upward force on it. The force equals the weight of the fluid it displaces.

FB=ρ ⁣fgVdeˊplaceˊ=m ⁣fgF_B=\rho_{\!f}gV_{\mathrm{déplacé}}=m_{\!f}g

Definition: Buoyant force

FBF_B acts upward and equals the weight of displaced fluid; ρf\rho_f is fluid density and VdispV_{\mathrm{disp}} is the object’s submerged volume. It arises because fluid pressure is greater beneath the object.

Vary fluid density and submerged volume to compare displaced-fluid weight with buoyancy.

Floating, sinking, and suspension

Compare weight P=mgP=mg with buoyancy. A floating object at rest has buoyancy equal to its weight and is only partly submerged. An object sinks if its weight exceeds the maximum buoyancy; an object whose average density is below that of the fluid can float.

Example: An object in water

An object displaces 2.0×10−3 m32.0\times10^{-3}\,\mathrm{m^3} of water. Find the buoyant force using ρ=1000 kg/m3\rho=1000\,\mathrm{kg/m^3} and g=9.8 m/s2g=9.8\,\mathrm{m/s^2}.

Solution

FB=ρgV=1000×9.8×0.002=19.6 NF_B=\rho gV=1000\times9.8\times0.002=19.6\,\mathrm N.

Quick check

Buoyancy depends on the displaced volume, not absolute depth: a fully submerged object of fixed volume in nearly incompressible water experiences nearly the same buoyant force at different depths. For a floating object, balance gives homobjectVmtotal=homfluidVmsubmerged ho_{ m object}V_{ m total}= ho_{ m fluid}V_{ m submerged}. Thus a less dense block floats with a smaller fraction submerged, while an object whose average density exceeds the fluid density cannot float freely.

Example: Submerged fraction of a floating object

A wooden block of density 600,mathrmkg/m3600,mathrm{kg/m^3} floats in water of density 1000,mathrmkg/m31000,mathrm{kg/m^3}. Force balance gives Vmsubmerged/Vmtotal=homwood/homwater=0.60V_{ m submerged}/V_{ m total}= ho_{ m wood}/ ho_{ m water}=0.60, so about 6060% of its volume lies below the surface. Adding a load makes the block sink farther, displacing more water and increasing buoyancy until forces balance again.

An object is fully immersed in a liquid. Its buoyant force equals:

A block floats at rest on water. Then:

References

  1. David Halliday, Robert Resnick, Jearl Walker (2018). Fundamentals of Physics