Physic Labs

Newtonian mechanics

Momentum

Momentum p=mv is a vector describing translational motion; its change is related to impulse.

Momentum combines mass and velocity and retains the direction of motion. A slow truck may still be harder to stop than a fast bicycle.

p⃗=mv⃗,J⃗=∫titfF⃗netdt=Δp⃗\vec p=m\vec v, \qquad \vec J=\int_{t_i}^{t_f}\vec F_{net}dt=\Delta\vec p

Definition: Momentum and impulse

In Newtonian mechanics, mm is constant and p⃗\vec p has units kg·m/s. Net-force impulse equals momentum change; for constant force, J⃗=F⃗netΔt\vec J=\vec F_{net}\Delta t.

Vary mass, velocity, force, and duration to explore momentum and impulse.

Impulse and momentum

Since p⃗=mv⃗\vec p=m\vec v, reversing velocity reverses momentum. Newton's second law is F⃗net=dp⃗/dt\vec F_{net}=d\vec p/dt; ma⃗m\vec a assumes constant mass.

Example: Braking a car

A 1000 kg car slows from 20 to 15 m/s. Find Δp\Delta p.

Solution

Taking the initial direction as positive, Δp=m(vf−vi)=1000(15−20)=−5000\Delta p=m(v_f-v_i)=1000(15-20)=-5000 kg·m/s; the sign is opposite the initial direction.

Quick check

When force varies with time, one cannot multiply an instantaneous value by the whole duration unless the force is constant. Impulse is the signed area under a force–time graph; in one dimension the average force is Favg=Deltap/DeltatF_{avg}=Delta p/Delta t. An air bag increases stopping time, so the same momentum change corresponds to a smaller average force on the passenger.

A useful procedure is to resolve momentum into components: px=mvxp_x=mv_x and py=mvyp_y=mv_y. For perpendicular motions, do not add momentum magnitudes; add each component, then use the Pythagorean theorem. For example, total components of 6 and 8 kg·m/s give a magnitude of 10 kg·m/s. In SI units, 11 N·s equals 11 kg·m/s, a useful dimensional check on the impulse theorem.

An object’s momentum may change over a finite interval according to the net impulse accumulated during that interval. In a vector component, a negative sign indicates the opposite direction, not a negative magnitude. State the reference frame and coordinate direction to avoid ambiguity. A final check should confirm both units and the direction of every component.

What is the momentum of a 2 kg object moving east at 3 m/s?

What equals the change in momentum?

References

  1. Young, Freedman (2019). University Physics