Newtonian mechanics
Conservation of momentum
Verify momentum conservation for a two-cart system on a horizontal plane: when the external impulse is negligible, the total momentum keeps its value after interaction. Also observe when changes with an external impulse .
Equipment
- Two carts m₁, m₂ on a horizontal plane (3D canvas, drag to rotate the view)
- Mass sliders m₁ (kg) and m₂ (kg)
- Initial-velocity sliders u₁ (m/s) and u₂ (m/s)
- External impulse J (N·s) and duration Δt (s) sliders
- Readout panel “P trước / P sau” (kg·m/s)
Procedure
Set masses and initial velocities
In section 1, move the four sliders m₁ (kg), m₂ (kg), u₁ (m/s), u₂ (m/s) — try u₁ > 0 and u₂ < 0 so the carts move toward each other (positive direction is to the right). Read the line “P trước = m₁u₁+m₂u₂” below and check it against computed from the slider values.
Check that total momentum stays constant
Keep the external impulse in section 2 at J = 0. Vary m₁, m₂, u₁, u₂ in section 1 and record P trước each time; the readout always states “P sau bằng P trước” when J ngoài ≈ 0 — the system is isolated horizontally so total momentum is conserved even though each cart changes velocity. Compare with .
Try a nonzero external force
In section 2, move the “Xung lượng ngoài J (N·s)” slider to positive then negative values, and also vary “Thời gian Δt (s)”. The readout “P sau = P trước + J ngoài” shows total momentum is no longer conserved: it shifts by exactly J, matching the impulse form of Newton's second law with mean external force .
Predict and compare
Choose m₁ = m₂ and u₂ = −u₁; predict P trước, then compare with the readout (expecting P = 0 — the momentum arrows cancel on the canvas). Then set J ≠ 0 and estimate P sau with before reading the value; repeat with two other (m, u) pairs to check when the conservation law applies.