Physic Labs

Problem 3

Monochromatic light of frequency ff shines on a metal with work function ϕ\phi; assume hf>ϕhf>\phi so photoelectrons are emitted, and let hh be Planck’s constant. Each photon transfers its energy to one electron, and subsequent collisions are neglected; ee is the magnitude of the electron charge. The stopping potential VsV_s means the magnitude of the reverse voltage just sufficient to prevent even the fastest electron from reaching the anode. (a) Write the energy balance for one photon and a maximum-energy electron. (b) Find Kmax⁡K_{\max} and VsV_s. (c) Predict how they depend on light frequency and intensity.
Kmax⁡=hf−ϕ,Vs=hf−ϕe;I↑⇒Ne−↑, Kmax⁡,Vs unchanged\boxed{K_{\max}=hf-\phi,\qquad V_s=\frac{hf-\phi}{e};\quad \mathcal I\uparrow\Rightarrow N_{e^-}\uparrow,\ K_{\max},V_s\text{ unchanged}}
problems.proof.analysis

The final expressions relate the fastest electron’s energy to the required stopping potential. The stopping potential is stated as a positive magnitude.