Physic Labs

Problem 2

An ideal source of emf V=10 VV=10\,\mathrm V is connected in series with resistors R1=2.0 ΩR_1=2.0\,\Omega and R2=3.0 ΩR_2=3.0\,\Omega. The circuit remains closed for t=60 st=60\,\mathrm s; neglect internal resistance and treat all values as constant. The resistors are ohmic and connected in series by ideal wires of negligible resistance. The source maintains a constant voltage for the entire time the circuit is closed. Take conventional current from the positive terminal through both resistors to the negative terminal; electrical energy dissipated is converted to heat. (a) Find the equivalent resistance and circuit current. (b) Determine the voltage across each resistor and check the loop rule. (c) Calculate the total power dissipated and the energy supplied in 60 s60\,\mathrm s.
Req=R1+R2=5.0 ΩR_{eq}=R_1+R_2=5.0\,\Omega
problems.proof.analysis

In series, the same current passes through each resistor, and their voltage drops add. Thus the source sees the sum of the resistances.