Physic Labs

Problem 3

Two masses m1=3.0 kgm_1=3.0\,\mathrm{kg} and m2=5.0 kgm_2=5.0\,\mathrm{kg} hang from a light inextensible string over a massless frictionless pulley; the system starts from rest. Take g=10 m s−2g=10\,\mathrm{m\,s^{-2}}. The string stays taut and does not slip on the pulley; its free rotation makes the tensions in the two segments equal. The masses move only vertically, so the lighter mass rises by the same distance and at the same speed that the heavier mass descends. Consider the motion after release. (a) Find the acceleration of each mass and the string tension. (b) Determine their speeds after 3.0 s3.0\,\mathrm s. (c) How far has each mass moved by then?
v=at=7.5 m s−1(t=3.0 s)v=at=7.5\,\mathrm{m\,s^{-1}}\quad(t=3.0\,\mathrm s)
problems.proof.analysis

Starting from rest with constant acceleration, the speed after three seconds is atat. This is the common speed magnitude of the two masses.