Physic Labs

Problem 2

In an insulated vessel, mh=0.20 kgm_h=0.20\,\mathrm{kg} of water at 80∘C80^\circ\mathrm C is mixed with mc=0.30 kgm_c=0.30\,\mathrm{kg} of water at 20∘C20^\circ\mathrm C. Water has specific heat c=4200 J kg−1K−1c=4200\,\mathrm{J\,kg^{-1}K^{-1}}; neglect the vessel heat capacity and heat loss. After mixing, the water reaches one uniform final temperature, with no evaporation or phase change. Heat is exchanged only between the two portions of water; the insulated vessel takes up no energy. Define heat as positive when the portion considered gains energy and negative when it loses energy. (a) Find the equilibrium temperature TfT_f. (b) Calculate the signed heat transferred by the hot water. (c) Find the heat received by the cold water and check energy conservation. (d) State the ordering of Tc,Tf,ThT_c,T_f,T_h.
Qh=mhc(Tf−Th)=−30240 JQ_h=m_hc(T_f-T_h)=-30240\,\mathrm J
problems.proof.analysis

The hot water cools, so Tf−Th<0T_f-T_h<0 and its signed heat is negative. Multiplying mass, specific heat, and temperature change gives joules.