Physic Labs

Problem 2

An initially uncharged capacitor C=100 μFC=100\ \mu\mathrm F is connected at t=0t=0 in series with a resistor R=10 kΩR=10\ \mathrm{k\Omega} and an ideal source of emf E=12E=12 V. Let q(t)q(t) be the capacitor charge and i(t)=q˙(t)i(t)=\dot q(t) the current. (a) Find the time constant τ\tau and the long-time charge q∞q_\infty. (b) Write expressions for q(t)q(t) and i(t)i(t). (c) Find when the charge reaches 90%90\% of its final value and the current at that instant.
1−e−t90=0.90⇒t90=τln⁡10=2.30 s1-e^{-t_{90}}=0.90\Rightarrow t_{90}=\tau\ln10=2.30\ \mathrm s
problems.proof.analysis

Set the ratio q/q∞=0.90q/q_\infty=0.90 and solve the exponent: e−t/τ=0.10e^{-t/\tau}=0.10. Taking the natural logarithm gives the time; with τ=1\tau=1 s it is just ln⁡10\ln 10.

problems.proof.pitfall. The 90% instant is not 0.9τ0.9\tau: exponential approach slows, so it takes τln⁡10\tau\ln 10, beyond one time constant but still short of asymptote.