Physic Labs

Problem 2

An initially uncharged capacitor C=100 μFC=100\ \mu\mathrm F is connected at t=0t=0 in series with a resistor R=10 kΩR=10\ \mathrm{k\Omega} and an ideal source of emf E=12E=12 V. Let q(t)q(t) be the capacitor charge and i(t)=q˙(t)i(t)=\dot q(t) the current. (a) Find the time constant τ\tau and the long-time charge q∞q_\infty. (b) Write expressions for q(t)q(t) and i(t)i(t). (c) Find when the charge reaches 90%90\% of its final value and the current at that instant.
q(t)=q∞(1−e−t/τ)=1.20×10−3(1−e−t) Cq(t)=q_\infty(1-e^{-t/\tau})=1.20\times10^{-3}\left(1-e^{-t}\right)\ \mathrm C
problems.proof.analysis

The general solution is the final charge q∞q_\infty plus an exponential term with a free constant. The condition q(0)=0q(0)=0 fixes that constant and gives the familiar 1−e−t/τ1-e^{-t/\tau} form.