Physic Labs

Problem 1

Masses m1=2m_1=2 kg and m2=3m_2=3 kg hang from the ends of a light inextensible string passing over a fixed frictionless pulley of negligible radius. The system is released from rest and the string remains taut. Take g=10g=10 m/s2^2 and choose each mass's direction of motion as positive. (a) Determine the direction and acceleration of each mass. (b) Find the string tension. (c) Find their speed after moving s=0.80s=0.80 m from rest, and check it by energy conservation.
m2g−T=m2a,T−m1g=m1am_2g-T=m_2a,\quad T-m_1g=m_1a
problems.proof.analysis

Project forces along each mass's motion. For descending m2m_2, weight minus tension equals m2am_2a; for rising m1m_1, tension minus weight equals m1am_1a.