Physic Labs

Problem 2

A parallel-plate capacitor has plate area AA, vacuum gap dd, and is initially connected to an ideal source that holds voltage VV. A homogeneous linear dielectric of relative permittivity κ>1\kappa>1 is slowly inserted until it fills the gap; neglect fringing. Let ε0\varepsilon_0 be the vacuum permittivity and C0=ε0A/dC_0=\varepsilon_0A/d. (a) Find the initial and final charge and field energy. (b) Find the work done by the source during insertion. (c) Find the mechanical work done by the field on the dielectric using energy conservation.
Ui=12C0V2,Uf=12κC0V2U_i=\frac12C_0V^2,\quad U_f=\frac12\kappa C_0V^2
problems.proof.analysis

For specified voltage, capacitor energy is U=CV2/2U=CV^2/2. The energy therefore increases in proportion to the capacitance.