Physic Labs

Problem 3

A thin converging lens in air has focal length f=20 cmf=20\,\mathrm{cm}, and a real upright object of height H=2.0 cmH=2.0\,\mathrm{cm} is placed u=30 cmu=30\,\mathrm{cm} in front of it. Use the Cartesian convention in which a real object has positive uu and a real image has positive vv, so 1/f=1/u+1/v1/f=1/u+1/v; neglect lens thickness. (a) Find the image distance vv. (b) Determine whether the image is real or virtual and upright or inverted. (c) Find its signed magnification and height.
H′=mH=−4.0 cmH'=mH=-4.0\,\mathrm{cm}
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Substituting the result into the relevant definition or law gives the next quantity. This connects the parts of the problem instead of treating their answers separately.